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Calculus 2: Trigonometric substitution

Integrate x316x2\frac{x^3}{\sqrt{16-x^2}} using trigonometric substitution.

Evaluate the integral x216x2dx\displaystyle \int \frac{\sqrt{x^2 - 16}}{x^2} \, dx using trigonometric substitution.

Using trigonometric substitution, simplify the expression a2u2\sqrt{a^2 - u^2}, where u=asinθu = a \sin\theta.

Complete the square for the expression x2+2xx^2 + 2x and then perform a trigonometric substitution.

Find the indefinite integral of xarccos(x)dx\displaystyle x \arccos(x) \, dx using trigonometric substitution.

Integrate 011x2+1dx\displaystyle \int_{0}^{1} \frac{1}{x^2 + 1} \, dx using trigonometric substitution.

Evaluate 1x2+4dx\displaystyle \int \frac{1}{x^2 + 4} \, dx using trigonometric substitution.

Evaluate 19x2dx\displaystyle \int \frac{1}{9 - x^2} \, dx using appropriate trigonometric substitution.

Show that the area of a circle is π×r2\pi \times r^2 using trigonometric substitution.

Evaluate x(x+5)2+4dx\displaystyle \int \frac{x}{\sqrt{(x+5)^2 + 4}} \, dx using trigonometric substitution after completing the square.

Evaluate 116(x4)2dx\displaystyle \int \frac{1}{16 - (x-4)^2} \, dx using trigonometric substitution after completing the square.

Evaluate the integral 9x2x2dx\displaystyle \int \frac{\sqrt{9 - x^2}}{x^2} \, dx using trig substitution, where you substitute x=3sinθx = 3\sin\theta.

Find the integral of 1x2x4dx\frac{\sqrt{1-x^2}}{x^4} \, dx by making the substitution x=cos(θ)x = \cos(\theta).

Find the integral 1y3y21dy\displaystyle \int \frac{1}{y^3 \sqrt{y^2 - 1}} \, dy.

Integrate dx(x2+22)3/2\displaystyle \frac{dx}{(x^2 + 2^2)^{3/2}} using the tangent substitution where x=2tan(θ)x = 2 \tan(\theta).

Compute the integral of 9x2dx\displaystyle \int \sqrt{9 - x^2} \, dx using the sine substitution where x=3sin(θ)x = 3\sin(\theta).

Integrate dx4x21\frac{dx}{\sqrt{4x^2 - 1}} using the secant substitution where x=12sec(θ)x = \frac{1}{2}\sec(\theta).

Solve the indefinite integral 4x216x2dx\displaystyle \int 4x^2 \sqrt{16 - x^2} \, dx using appropriate substitution.

Indefinite integral of 1x225dx\displaystyle \int \frac{1}{\sqrt{x^2 - 25}} \, dx using trigonometric substitution.