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Calculus 2: Separable differential equations

Solve the differential equation dydx=x2y2\frac{dy}{dx} = \frac{x^2}{y^2} using separation of variables to find the general solution and the particular solution given the initial condition y(1)=2y(1) = 2.

Solve the differential equation dydx=xy\frac{dy}{dx} = xy using separation of variables, given the initial condition y(0)=5y(0) = 5, and find both the general and particular solutions.

Solve the differential equation dydx=y2+1\frac{dy}{dx} = y^2 + 1 and find the general solution as well as the particular solution given the initial condition y(1)=0y(1) = 0.

Solve for y given dydx=x2y2\frac{dy}{dx} = \frac{x^2}{y^2}.

Solve for yy given dydx=6x22y+cos(y)\frac{dy}{dx} = \frac{6x^2}{2y + \cos(y)}.

dy/dx = xeyy. Given the initial condition y(0)=0y(0) = 0, solve for yy.

Solve the separable differential equation dYdX=XYeX2\frac{dY}{dX} = -\frac{X}{Y}e^{X^2} given the initial condition that the solution must pass through the point (0,1).

Solve the differential equation x2+1dydx=xyx^2 + 1 \frac{dy}{dx} = x \cdot y by separating variables.

Verify that the solution to the exponential growth equation is y=cekty = ce^{kt}, where c is a constant.

Solve a first order differential equation using the method of separation of variables.

Solve the differential equation y=xyy2+1y' = \frac{xy}{y^2 + 1} using separation of variables.

Solve the differential equation dydx=5x\frac{dy}{dx} = 5x.

Solve the differential equation dydx=3x2ey\frac{dy}{dx} = 3x^2 e^{-y} that satisfies the initial condition y(0)=0y(0) = 0.