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Calculus 1

Use implicit differentiation to take the derivative of yy with respect to xx for the following equation

y5+2y=x2y^5 + 2y = x^2

Find dydx\frac{dy}{dx} when x3+3y4=2x+7x^3 + 3y^4 = 2x + 7

Find the derivative of yy with respect to xx for the following equation

y(x+4)=x23y(x+4) = x^2 - 3

Find dydx\frac{dy}{dx} for x2+y3=log(x+y)x^2 + y^3 = \log{(x + y)}

Find the derivative, yy^{\prime} of the following implicit function

y=tan1(xy)y = \tan^{-1}(xy)

For the following equation, differentiate implicitly to find dydx\frac{dy}{dx}

e(x+y)=sin(x)+cos(y)e^{(x + y)} = \sin{(x)} + \cos{(y)}

Find the tangent line to the curve xy+ln(xy2)=1xy + \ln{(xy^2)} = 1 at the point (1,1)(1,1)

Find dydx\frac{dy}{dx} and the slope of the tangent line at (2,1)(-2, 1) for the curve given by

2x23y3=52x^2 - 3y^3 = 5

Find dydx\frac{dy}{dx} and the slope of the tangent line at (0,3) for the curve given by

y3+x2y5x4=27y^3 + x^{2}y^{5} - x^4 = 27

Determine the first and second derivatives, dydx\frac{dy}{dx} and d2ydx2\frac{d^{2}y}{dx^2} for the following equation

x2+xy=4x^2 + xy = 4

Show that ddx(arcsinx)=x1x2\frac{d}{dx}(\arcsin{x}) = \frac{x^{\prime}}{\sqrt{1 - x^2}}

Determine the derivative of the following inverse trig function

f(x)=arctan(x)f(x) = \arctan{(\sqrt{x})}

Determine the derivative of the inverse trigonometric function

f(x)=sec1(5x)f(x) = \sec^{-1}{(5x)}

Find the derivative of f(x)=2arccos(x3)f(x) = 2\arccos{(\frac{x}{3})}

Determine the derivative of f(t)=sin(arccos(t))f(t) = \sin{(\arccos{(t)})}

Let f(x)=tan(x)f(x) = \tan{(x)} on the interval π2\frac{-\pi}{2} < xx < π2\frac{\pi}{2}

What is ddx(arctan(x))\frac{d}{dx}(\arctan{(x)}) ?

Show that for y=cos1(x)y = \cos^{-1}(x) the first derivative, dydx=1x2+1\frac{dy}{dx} = \frac{1}{x^2 + 1}

For the following function, find the first derivative

θ=tan1(2r)πr\theta = \frac{\tan^{-1}(2r)}{\pi{r}}

Find the derivative of the following hyperbolic function

f(x)=sin(sinh(x))f(x) = \sin{(\sinh{(x)})}

Find the derivative of f(x)=(sinh1(x))32f(x) = {(\sinh^{-1}(x))}^{\frac{3}{2}}