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Calculus 2

Convert a rectangular equation, such as x+y=3x + y = 3, to a polar equation.

Graph the polar equation r=2cos(θ)r = 2 \cos(\theta), and verify by converting to rectangular form.

Graph polar coordinates with given radius and angle.

Graph the equation where r=acos(2θ)r = a \cos(2\theta).

Find the equation of the tangent line for the polar equation r=2+3cos(θ)r = 2 + 3\cos(\theta) when θ=π2\theta = \frac{\pi}{2}.

Write the equation of the tangent line for the polar equation r=32sin(θ)r = 3 - 2\sin(\theta) when θ=π\theta = \pi.

Evaluate the double integral 02π2π2er2rdrdθ\displaystyle \int_{0}^{2} \int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} e^{-r^2} r \, dr \, d\theta by converting it to polar coordinates in the region bounded by x=4y2x = \sqrt{4 - y^2} and the y-axis.

Solve for y given dydx=x2y2\frac{dy}{dx} = \frac{x^2}{y^2}.

Solve for yy given dydx=6x22y+cos(y)\frac{dy}{dx} = \frac{6x^2}{2y + \cos(y)}.

dy/dx = xeyy. Given the initial condition y(0)=0y(0) = 0, solve for yy.

Solve the separable differential equation dYdX=XYeX2\frac{dY}{dX} = -\frac{X}{Y}e^{X^2} given the initial condition that the solution must pass through the point (0,1).

Solve the differential equation: dydx=x+xy2\frac{dy}{dx} = x + x y^2 with the initial condition y(0)=1y(0) = -1.

Solve the differential equation x2+1dydx=xyx^2 + 1 \frac{dy}{dx} = x \cdot y by separating variables.

Verify that the solution to the exponential growth equation is y=cekty = ce^{kt}, where c is a constant.

Solve a first order differential equation using the method of separation of variables.

Solve the differential equation y=xyy2+1y' = \frac{xy}{y^2 + 1} using separation of variables.

Solve the differential equation dydx=5x\frac{dy}{dx} = 5x.

Solve the differential equation dydx=3x2ey\frac{dy}{dx} = 3x^2 e^{-y} that satisfies the initial condition y(0)=0y(0) = 0.