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Calculus 2

Try using the integral test on your own for the series n=1en\sum_{n=1}^{\infty} e^n and determine if it converges or diverges.

If you look at the improper interval and the improper integral converges or diverges, whatever it does, the same is true of the series.

Calculate whether the series n=11n2\sum_{n=1}^{\infty} \frac{1}{n^2} is convergent using the integral test, and estimate its sum.

Using the comparison test, determine if the series n=112n+1\displaystyle \sum_{n=1}^{\infty} \frac{1}{2^n + 1} is convergent by comparing it to the series n=112n\displaystyle \sum_{n=1}^{\infty} \frac{1}{2^n}.

Determine whether the series n=152n2+4n+3\displaystyle \sum_{n=1}^{\infty} \frac{5}{2n^2 + 4n + 3} is convergent using the comparison test.

Determine whether the series represented by the function is convergent or divergent using the integral test for the function: 112xdx\displaystyle \int_{1}^{\infty} \frac{1}{2^x} \, dx

Determine whether the series represented by the function is convergent or divergent using the integral test for the function: 1xx2+1dx\displaystyle \int_{1}^{\infty} \frac{x}{x^2 + 1} \, dx

Consider the series that starts from one goes to infinity: (1)n1n(-1)^n \cdot \frac{1}{n}. Will the alternating harmonic series converge or diverge?

Consider the series which goes from 1 to infinity: (1)n+15n+32n7(-1)^{n+1} \cdot \frac{5n + 3}{2n - 7}. Will this series converge or diverge?

Consider the series: (1)n+15n\frac{(-1)^{n+1}}{5^n}. Will the series converge or diverge?

Consider the series (1)nnln(n)(-1)^n \cdot \frac{n}{\ln(n)}. Will the series converge or diverge?

Let's say the series is (1)n+1ln(n)n(-1)^{n+1} \cdot \frac{\ln(n)}{n}. Will it converge or diverge?

Consider the series cos(nπ)n\frac{\cos(n \pi)}{n}. Can we apply the alternating series test to it?

Take the series (1)n1Bn(-1)^{n-1} B_n, where BnB_n is positive. Determine if the series is convergent or divergent based on if Bn+1BnB_{n+1} \leq B_n and limnBn=0\lim_{{n \to \infty}} B_n = 0.

Apply the alternating series test to different series to determine convergence or divergence: (1)n3n12n+1(-1)^n \cdot \frac{3n-1}{2n+1} and (1)n+1n2n3+4(-1)^{n+1} \cdot \frac{n^2}{n^3+4}.

Use the ratio test to determine the convergence of the series nnn!\frac{n^n}{n!}.

Given an alternating series (1)n11n\sum (-1)^{n-1} \frac{1}{n}, determine if the series converges using the Alternating Series Test.

Determine if the series n=1(1)n14n1\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{4n-1} converges using the alternating series test.

Determine if the series n=1n+13n+2\sum_{n=1}^{\infty} \frac{n+1}{3n+2} converges or diverges, and justify your answer.

Determine if the series n=1nn2+1\sum_{n=1}^{\infty} \frac{n}{n^2+1} converges using the alternating series test.