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Calculus 3: Surface parameterization

Find a parameterization for the cone using cylindrical coordinates, specifically with parameters r and theta, where the height of the cone is z=rz=r, and the cone is bounded by z3z \leq 3.

Parametrize the cylindrical surface given by the equation x2+(y2)2=4x^2 + (y - 2)^2 = 4.

Parametrize the sphere given by the equation x2+y2+z2=9x^2 + y^2 + z^2 = 9 using spherical coordinates.

Given the parametrization x = u, y = v, and z=u2+v2z=\sqrt{u^2 + v^2}, determine the rectangular equation.

Given the parametrization x=3usinvx=3u\sin v, y=3ucosvy=3u\cos v, and z=u2z=u^2, determine the rectangular equation.

Using two parameters, parametrize the surface of a torus (doughnut shape) in three dimensions, considering a circle of radius aa at a distance bb from the center (z-axis), and varying the parameters to map the surface of the torus.

How do you actually go from an s and a t that goes from 00 to 2π2\pi, in both cases, and turn it into a three-dimensional position vector-valued function that would define this surface?

Determine the resulting shape when both T and S vary freely in the function representing a torus.

Consider the surface given by x=ucos(v),y=usin(v),z=vx = u \cos(v), y = u \sin(v), z = v. Set up the integral for the surface integral of a function ff over this surface.