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Limit Comparison Test for Series Convergence2

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Use the limit comparison test to see if the series 1n2+2\frac{1}{\sqrt{n^2 + 2}} converges or diverges.

The limit comparison test is a useful tool in determining the convergence or divergence of series, particularly when dealing with series that involve complex expressions. To effectively apply this test, it is essential to identify another series with a known convergence behavior that can be compared to the given series. This often involves recognizing standard benchmark series, such as p-series or geometric series, which have well-established convergence criteria.

In the context of the problem at hand, it is helpful to note the structure of the term 1n2+2\frac{1}{\sqrt{n^2 + 2}}, which resembles a p-series of the form 1np\frac{1}{n^p}. The challenge lies in identifying an appropriate comparison series, which in this case could be 1n\frac{1}{n}, given that the additional constant inside the square root becomes negligible for large nn.

Once an appropriate comparison series is identified, the limit comparison test involves evaluating the limit of the ratio of the terms from the two series as nn approaches infinity. If the result is a finite non-zero number, then both series either converge or diverge together. This strategic approach highlights the importance of understanding series behavior in the broader context of sequence and series convergence, a fundamental topic in calculus.

Posted by Gregory 32 minutes ago

Related Problems

Using the comparison test, determine if the series n=112n+1\displaystyle \sum_{n=1}^{\infty} \frac{1}{2^n + 1} is convergent by comparing it to the series n=112n\displaystyle \sum_{n=1}^{\infty} \frac{1}{2^n}.

Determine whether the series n=152n2+4n+3\displaystyle \sum_{n=1}^{\infty} \frac{5}{2n^2 + 4n + 3} is convergent using the comparison test.

Determine if the series 13n+5\frac{1}{3^n + 5} converges or diverges using the limit comparison test.

Suppose that the two series ana_n (the series we care about) and bnb_n (the series we will use for comparison) have positive terms. If the series bnb_n is convergent and the terms anbna_n \leq b_n for all nn, then the series ana_n converges.