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Limit Comparison Test for Series Convergence23

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Determine if the series 13n+5\frac{1}{3^n + 5} converges or diverges using the limit comparison test.

In the study of infinite series, determining whether a series converges or diverges is a fundamental concept, especially in calculus and analysis courses. The limit comparison test is a powerful tool used to determine the behavior of a series by comparing it to another series whose convergence properties are already known. This approach is particularly useful when dealing with complex expressions that do not easily lend themselves to more straightforward convergence tests, like the p-series test or geometric series test.

The limit comparison test states that for two series with positive terms, sum an and sum bn, if the limit of an/bn as n approaches infinity is a positive finite number, both series either converge or diverge together. This method relies on the intuitive idea that if two sequences behave similarly for large values of n, then their series should behave similarly in terms of convergence. This requires selecting a bn that is simple enough to allow the limit to be evaluated but still reflects the dominant behavior of an.

In this particular problem, the series given by 1/(3n + 5) is under analysis. By selecting an appropriate comparative series, often a geometric or p-series, you can exploit the properties of the more familiar series to establish convergence or divergence. This approach highlights the strategic aspect of problem-solving in mathematics, where identifying symmetries or analogous situations allows existent theoretical results to be applied effectively, simplifying the problem-solving process.

Posted by Gregory 32 minutes ago

Related Problems

Attempt comparing series with non-standard terms using the limit comparison test.

Using the comparison test, determine if the series n=112n+1\displaystyle \sum_{n=1}^{\infty} \frac{1}{2^n + 1} is convergent by comparing it to the series n=112n\displaystyle \sum_{n=1}^{\infty} \frac{1}{2^n}.

Determine whether the series n=152n2+4n+3\displaystyle \sum_{n=1}^{\infty} \frac{5}{2n^2 + 4n + 3} is convergent using the comparison test.

Suppose that the two series ana_n (the series we care about) and bnb_n (the series we will use for comparison) have positive terms. If the series bnb_n is convergent and the terms anbna_n \leq b_n for all nn, then the series ana_n converges.