Skip to Content

Convergence of Geometric Series

Home | Calculus 2 | Series and the integral test | Convergence of Geometric Series

Evaluate whether a geometric series with terms A times R^(N-1) is convergent or divergent given different values of R.

Understanding whether a geometric series converges or diverges is a foundational concept in series analysis. A geometric series has the form where each term is derived by multiplying the previous term by a fixed number, known as the common ratio. If the absolute value of this common ratio is less than one, the series converges, meaning it approaches a finite limit. Otherwise, if the absolute value of the common ratio is equal to or greater than one, the series diverges, meaning it grows without bound or oscillates indefinitely.

To evaluate the convergence of a geometric series, consider its general term, which can be expressed in the form A times R raised to the power of N minus one, where A is the initial term, R is the common ratio, and N is the term number. The process of determining convergence involves analyzing the properties of the common ratio R: specifically, checking its magnitude relative to 1. This aligns with the wider concept of series and convergence tests, which aim to determine the behavior of infinite series in calculus.

In the context of solving such problems, it's crucial to seamlessly apply these foundational rules to discern between convergent and divergent scenarios. Understanding this concept provides a stepping stone into more advanced topics involving series, such as power series or Taylor series expansions, which rely heavily on understanding the nature of convergence.

Posted by grwgreg 15 days ago

Related Problems

Find the sum of an infinite geometric series where the first term is 100 and the common ratio is 12\frac{1}{2}.

Using the summation notation Σ\Sigma, calculate the sum of the geometric series from k=2k=2 to k=7k=7 with the geometric rule ak=12k×2a_k = \frac{1}{2}^k \times 2.

Explore whether the infinite series from n equals 1 to infinity of 1n2\frac{1}{n^2} converges or diverges using the integral test.

For a series represented with a corresponding function over an interval, use the integral test to determine convergence.