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Convergence of Series Using Root Test

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Use the root test to determine if the series from 1 to infinity of 14n\frac{1}{4^n} will converge or diverge.

The root test is a powerful tool in determining the convergence or divergence of an infinite series. It is particularly useful when the series involves expressions that lend themselves to taking roots. To apply the root test, one examines the nth root of the absolute value of the nth term of the series. The key concept is evaluating the limit of this nth root as n approaches infinity. If this limit is less than one, the series converges absolutely, indicating that it sums to a finite value, regardless of the specific order of terms. If the limit is greater than one, the series diverges, meaning it does not approach a finite sum. If the limit equals one, the root test is inconclusive, and other methods must be used to determine convergence or divergence.

In the case of the given series, identifying the pattern that emerges after applying the nth root can swiftly lead to a conclusion about its convergence behavior without delving into term-by-term analysis. This efficiency is one of the main strengths of the root test, making it a preferred method for appropriately structured series. Understanding when and how to apply the root test not only helps in solving individual problems but also builds a deeper comprehension of series behavior and the foundational principles of calculus that govern such analyses. By mastering tests like these, students can strengthen their ability to tackle more complex series and integrals in advanced calculus.

Posted by Gregory 32 minutes ago

Related Problems

Apply the ratio test to series involving factorial terms and powers, such as those with n!n! or similar structures.

Use the ratio test to determine the convergence of the series nnn!\frac{n^n}{n!}.

Use the root test to determine if the series (3+5n2+3n)n\left(\frac{3+5n}{2+3n}\right)^n converges, diverges, or is inconclusive.

Apply the root test to the series (1n2+1n)n\left(\frac{1}{n^2 + \frac{1}{n}}\right)^n.