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Convergence of Series Using Direct Comparison Test

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Use the direct comparison test to determine if the series                                                             u000f n=1 }                                                               $n=1}^{        {   {  

When faced with the series given in the problem, the primary goal is to determine its convergence or divergence using the direct comparison test. This requires finding a second series that is either consistently larger or smaller than the given series and whose convergence properties are already known. Essentially, the direct comparison test is a valuable tool in determining the behavior of series by leveraging known series.

In this particular problem, the challenge lies in identifying or constructing a series that effectively bounds the given series above or below for all terms. The series rac{1}{4 + \ n}\\ decreases as nn increases, which suggests that it might be comparable to a well-known convergent or divergent series. A useful approach might be to simplify or manipulate the denominator to identify a simpler series with similar behavior, such as a p-series, which is a cornerstone in series comparison due to its well-defined convergence properties.

Conceptual understanding of the direct comparison test and its applications extends beyond this single series problem. It plays a critical role when dealing with complex series, where direct calculation or standard tests (like the p-series or geometric series tests) may not easily apply. Understanding how to dissect a series and ingeniously select a comparator series requires practice and deep familiarity with various types of series and their convergence behaviors.

Posted by Gregory 32 minutes ago

Related Problems

Using the comparison test, determine if the series n=112n+1\displaystyle \sum_{n=1}^{\infty} \frac{1}{2^n + 1} is convergent by comparing it to the series n=112n\displaystyle \sum_{n=1}^{\infty} \frac{1}{2^n}.

Determine whether the series n=152n2+4n+3\displaystyle \sum_{n=1}^{\infty} \frac{5}{2n^2 + 4n + 3} is convergent using the comparison test.

Use the direct comparison test to determine if the series n=12n7n+8\sum_{n=1}^{\infty} \frac{2^n}{7^n + 8} converges or diverges.

Determine the convergence or divergence of the series n=11n4+5\sum_{n=1}^{\infty} \frac{1}{\sqrt{n^4 + 5}}.