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Convergence of Series Using Comparison Tests

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For series that resemble quotient forms, like nn3+1\frac{n}{n^3 + 1}, determine convergence using the comparison or limit comparison test.

When faced with series that resemble quotient forms, like the series given here, one effective method to determine convergence is using the comparison test or its variant, the limit comparison test. These tests are powerful tools in analyzing series, particularly when the terms can be compared to a known benchmark series that converges or diverges. The key idea here is to either directly compare the series in question with another series where the convergence behavior is known or to evaluate the limit of the ratios of the general terms of the two series.

In the comparison test, you typically assert a relationship between the terms of your series and those of a comparator series. If you can show that each term of your series is smaller than a convergent series, your series converges as well. Conversely, if each term is larger than a divergent series, your series diverges. Meanwhile, the limit comparison test requires finding the limit of the quotient of terms from two series. If this limit is a positive finite number, both series either converge or diverge together.

It’s crucial to choose suitable comparator series carefully. Often, polynomial or harmonic series serve as useful benchmarks. Also, understanding the asymptotic behavior — how the terms of the series behave as n approaches infinity — is essential in these comparisons, as subtle differences may qualitatively affect the convergence outcome. Mastery of these tests will enhance your problem-solving toolkit, especially when dealing with complex series tests in a mathematical analysis context.

Posted by grwgreg 15 days ago

Related Problems

Attempt comparing series with non-standard terms using the limit comparison test.

Using the comparison test, determine if the series n=112n+1\displaystyle \sum_{n=1}^{\infty} \frac{1}{2^n + 1} is convergent by comparing it to the series n=112n\displaystyle \sum_{n=1}^{\infty} \frac{1}{2^n}.

Determine whether the series n=152n2+4n+3\displaystyle \sum_{n=1}^{\infty} \frac{5}{2n^2 + 4n + 3} is convergent using the comparison test.