Search Insert Position
Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You must write an algorithm with O(log n) runtime complexity.
class Solution {
public int searchInsert(int[] nums, int target) {
if(nums == null || nums.length == 0) return 0;
int n = nums.length;
int l = 0;
int r = n - 1;
while(l < r){
int m = l + (r - l)/2;
if(nums[m] == target) return m;
else if(nums[m] > target) r = m; // right could be the result
else l = m + 1; // m + 1 could be the result
}
// 1 element left at the end
// post-processing
return nums[l] < target ? l + 1: l;
}
}Related Problems
Given an array of distinct integers candidates and a target integer target, return a list of all unique combinations of candidates where the chosen numbers sum to target. You may return the combinations in any order.
The same number may be chosen from candidates an unlimited number of times. Two combinations are unique if the frequency of at least one of the chosen numbers is different.
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For example, the pair [0, 1], indicates that to take course 0 you have to first take course 1.
Return true if you can finish all courses. Otherwise, return false.
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Integers in each row are sorted in ascending from left to right.
Integers in each column are sorted in ascending from top to bottom.
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