Skip to Content

Best time to buy and sell stock II

Home | Coding Interviews | Greedy Algorithms | Best time to buy and sell stock II

You are given an integer array prices where prices[i] is the price of a given stock on the ith day.

On each day, you may decide to buy and/or sell the stock. You can only hold at most one share of the stock at any time. However, you can buy it then immediately sell it on the same day.

Find and return the maximum profit you can achieve.

class Solution:
    def maxProfit(self, prices: List[int]) -> int:

        price_gain = []
        
        for idx in range( len(prices)-1 ):
            
            if prices[idx] < prices[idx+1]:
                
                price_gain.append( prices[idx+1]- prices[idx])
                
        return sum( price_gain )

Posted by Jamie Meyer 9 months ago

Related Problems

You are given an array of CPU tasks, each represented by letters A to Z, and a cooling time, n. Each cycle or interval allows the completion of one task. Tasks can be completed in any order, but there's a constraint: identical tasks must be separated by at least n intervals due to cooling time.

Return the minimum number of intervals required to complete all tasks.

Given an array nums with n integers, your task is to check if it could become non-decreasing by modifying at most one element.

We define an array is non-decreasing if nums[i] <= nums[i + 1] holds for every i (0-based) such that (0 <= i <= n - 2).

Given a string s, remove duplicate letters so that every letter appears once and only once. You must make sure your result is the smallest in lexicographical order among all possible results.

Given a positive integer n, return a string representing the smallest positive integer such that the product of its digits is equal to n, or "-1" if no such number exists.