Volume Under a Paraboloid23456
Find the volume under the surface and above the -plane.
This problem involves finding the volume of a solid region bounded above by a paraboloid surface and below by the xy-plane. The given surface equation is a standard form of an elliptic paraboloid, and the task is to calculate the volume under this paraboloid using integration techniques. Here, the surface is expressed as z equals nine minus the sum of the squares of x and y, a common form encountered in multivariable calculus.
To tackle this problem, one effective method is to employ double integration over a circular region. The geometry suggests that the limits of integration will be circular, making it intuitive to switch to polar coordinates, where x is represented as r times the cosine of theta and y as r times the sine of theta. This transformation simplifies the integration process as the bounds become more manageable, matching the circular symmetry of the paraboloid.
Emphasizing the strategy, understanding the choice of coordinate transformation and the setup of the integrals is crucial. The integrand evolves naturally from the expression of z, and the bounds for r and theta are derived from the circular footprint of the surface on the xy-plane. This problem reinforces the powerful technique of coordinate changes in evaluating double integrals, particularly when symmetry is present. Additionally, it serves as a practical application of interpreting geometrical relationships and using calculus tools to find volumes in multivariable contexts.
Related Problems
Using the double integral method, find the volume of the given surface projected onto the xy-plane over a specified rectangular region.
Compute the volume under the surface given by over the rectangular region where is between and and is between and .
Set up a generic integral for the region bounded by the curves and , using the order of iteration .
Find the surface area of the part of the function that lies inside the circle using double integrals.