General Chemistry 1: Enthalpy

C$_2$H$_4$ + 6 F$_2$ $\longrightarrow$ 2 CF$_4$ + 4 HF

Find the $\triangle$H of the above reaction given:

H$_2$ + F$_2$ $\longrightarrow$ 2 HF $\triangle$H = -537 kJ

2 C + 2 H$_2$ $\longrightarrow$ C$_2$H$_4$ $\triangle$H = +52 kJ

CF$_4$ $\longrightarrow$ C + 2 F$_2$ $\triangle$H = +680 kJ